100-140x+49x^2=0

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Solution for 100-140x+49x^2=0 equation:



100-140x+49x^2=0
a = 49; b = -140; c = +100;
Δ = b2-4ac
Δ = -1402-4·49·100
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{140}{98}=1+3/7$

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